Difference between revisions of "Torque Steer"
SpookySimon (talk | contribs) (step1) |
SpookySimon (talk | contribs) (→Example Calculation: step 2&3) |
||
| Line 7: | Line 7: | ||
'''Step 1: Polar Moment of Inertia''' | '''Step 1: Polar Moment of Inertia''' | ||
| − | The moment of inertia (J) for a hollow shaft is | + | The moment of inertia (J) for a hollow shaft is calculated as follows: |
| + | :π/32 * (D<sup>4</sup>-d<sup>4</sup>) | ||
| + | |||
| + | Using values from an RCV axle below, we can find J. | ||
{| class="wikitable" | {| class="wikitable" | ||
| Line 15: | Line 18: | ||
|} | |} | ||
| − | Shaft Area of Inertia | + | Shaft Area of Inertia: 0.034076in<sup>2</sup> |
'''Step 2: Calculate Torsional Stiffness''' | '''Step 2: Calculate Torsional Stiffness''' | ||
| − | + | We will use 4130 chromoly steel as our half-shaft material, most steels have a very similar shear modulus (G) so this choice is not a driving factor in the result. The torsional stiffness (k) of the shaft will be found using the following formula and values: | |
| + | :k = G*J / L | ||
| − | 4130 Shear Modulus | + | {| class="wikitable" |
| − | + | | Shaft Material || 4130 Steel | |
| − | Left Shaft Length | + | |- |
| − | + | | 4130 Shear Modulus || 1.16e+7 psi | |
| − | Right Shaft Length | + | |- |
| − | + | | Left Shaft Length (L<sub>L</sub>) || 15 in | |
| − | + | |- | |
| + | | Right Shaft Length (L<sub>R</sub>) || 19 in | ||
| + | |} | ||
Left Torsional Stiffness (k<sub>L</sub>): 38.3379023 lb-ft / degree | Left Torsional Stiffness (k<sub>L</sub>): 38.3379023 lb-ft / degree | ||
| Line 33: | Line 39: | ||
Right Torsional Stiffness (k<sub>R</sub>): 30.26401 lb-ft / degree | Right Torsional Stiffness (k<sub>R</sub>): 30.26401 lb-ft / degree | ||
| − | + | '''Step 3: Find Torque''' | |
| + | |||
| + | Our last input value that we need to find is the torque experience by the driveshafts. This is the torque output by the motor and transmitted through the final drive ratio. The maximum torque applied to the driveshafts by the engine will be during launch, when the wheels are still and we can assume a perfect launch by the driver, applying the maximal engine torque for the split second we are examining. | ||
| − | Max Torque from Engine | + | Max Torque from Engine: 40 lb-ft |
Final Drive Ratio: 3.55 | Final Drive Ratio: 3.55 | ||
Revision as of 12:00, 23 January 2023
Torque Steer is a yawing effect caused by unequal stiffness driveshafts, most frequently due to unequal length. A stiffer shaft will turn the wheel further than a softer shaft for the same input torque.
Example Calculation
Using ballpark values, we can calculate an approximate torque steer value for a generalized FSAE car.
Step 1: Polar Moment of Inertia
The moment of inertia (J) for a hollow shaft is calculated as follows:
- π/32 * (D4-d4)
Using values from an RCV axle below, we can find J.
| Shaft OD (D) | 0.8" |
| Shaft ID (d) | 0.5" |
Shaft Area of Inertia: 0.034076in2
Step 2: Calculate Torsional Stiffness
We will use 4130 chromoly steel as our half-shaft material, most steels have a very similar shear modulus (G) so this choice is not a driving factor in the result. The torsional stiffness (k) of the shaft will be found using the following formula and values:
- k = G*J / L
| Shaft Material | 4130 Steel |
| 4130 Shear Modulus | 1.16e+7 psi |
| Left Shaft Length (LL) | 15 in |
| Right Shaft Length (LR) | 19 in |
Left Torsional Stiffness (kL): 38.3379023 lb-ft / degree
Right Torsional Stiffness (kR): 30.26401 lb-ft / degree
Step 3: Find Torque
Our last input value that we need to find is the torque experience by the driveshafts. This is the torque output by the motor and transmitted through the final drive ratio. The maximum torque applied to the driveshafts by the engine will be during launch, when the wheels are still and we can assume a perfect launch by the driver, applying the maximal engine torque for the split second we are examining.
Max Torque from Engine: 40 lb-ft
Final Drive Ratio: 3.55
Torque Seen by Driveshaft: 142 lb-ft
Step 4: Find Shaft Twist
phi = T / k
Left Shaft Twist (phiL): 3.704 degrees
Right Shaft Twist (phiR): 4.692 degrees
Step 5: Find Vehicle Yaw
Tire travel (T) = Shaft twist/360 * Tire Circumference
Yaw = arcsin(Tmax-Tmin / Track Width)
Circumference of Tire: 56.52 in
Left Tire Travel: 0.582 in
Right Tire Travel: 0.737 in
Rear Track: 36 in
Yaw: 0.247 degrees