Suspension Forces - Revision history

SpookySimon: /* Inboard vs outboard drive/brake */ subscript

2024-04-09T15:40:02Z

Inboard vs outboard drive/brake: subscript

SpookySimon: /* See Also */ moving note to talk page

2022-07-26T16:38:53Z

SpookySimon: /* See Also */ reporting broken link

2022-07-26T16:09:27Z

Normalski: /* Inboard vs outboard drive/brake */

2021-03-15T17:55:23Z

Inboard vs outboard drive/brake

Normalski at 17:53, 15 March 2021

2021-03-15T17:53:19Z

FsaeIllumina: fixed broken 'see also' link

2021-01-14T20:06:07Z

fixed broken 'see also' link

FsaeIllumina: fix url

2021-01-14T17:35:01Z

fix url

FsaeIllumina: added link to excel file

2021-01-14T17:34:11Z

added link to excel file

FsaeIllumina: Undo revision 2025 by FsaeIllumina (talk)

2021-01-14T17:32:48Z

Undo revision 2025 by FsaeIllumina (talk)

FsaeIllumina: move video

2021-01-14T17:32:23Z

move video

← Older revision		Revision as of 15:40, 9 April 2024
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−	For an inboard drive/brake, the driveshaft helps and reacts the moment that originates from the contact patch as the driveshaft itself is being stressed. For outboard drive/brake, the driveshaft is not stressed, and cannot transmit the torque like in the inboard scenario. Therefore, with an inboard layout, the driveshaft acts like a 7th link and typically reduces the loads going through the other suspension links. This can be compensated for in the calculation by the additional moment, My, when analysing inboard drive/brakes.	+	For an inboard drive/brake, the driveshaft helps and reacts the moment that originates from the contact patch as the driveshaft itself is being stressed. For outboard drive/brake, the driveshaft is not stressed, and cannot transmit the torque like in the inboard scenario. Therefore, with an inboard layout, the driveshaft acts like a 7th link and typically reduces the loads going through the other suspension links. This can be compensated for in the calculation by the additional moment, M<sub>y</sub>, when analysing inboard drive/brakes.

	===Theory===		===Theory===

@@ Line 63: / Line 63: @@
 [http://scholarworks.csun.edu/bitstream/handle/10211.3/123383/Flickinger-Evan-thesis-2014.pdf;sequence=1 DESIGN AND ANALYSIS OF FORMULA SAECAR SUSPENSION MEMBERS]
-[http://www.iaeme.com/MasterAdmin/uploadfolder/IJMET_07_02_018/IJMET_07_02_018.pdf FORCE CALCULATION IN UPRIGHT OF A FSAE RACE CAR] sorry, link broken
+[http://www.iaeme.com/MasterAdmin/uploadfolder/IJMET_07_02_018/IJMET_07_02_018.pdf FORCE CALCULATION IN UPRIGHT OF A FSAE RACE CAR]
 [[Category:Suspension]]

@@ Line 63: / Line 63: @@
 [http://scholarworks.csun.edu/bitstream/handle/10211.3/123383/Flickinger-Evan-thesis-2014.pdf;sequence=1 DESIGN AND ANALYSIS OF FORMULA SAECAR SUSPENSION MEMBERS]
-[http://www.iaeme.com/MasterAdmin/uploadfolder/IJMET_07_02_018/IJMET_07_02_018.pdf FORCE CALCULATION IN UPRIGHT OF A FSAE RACE CAR]
+[http://www.iaeme.com/MasterAdmin/uploadfolder/IJMET_07_02_018/IJMET_07_02_018.pdf FORCE CALCULATION IN UPRIGHT OF A FSAE RACE CAR] sorry, link broken
 [[Category:Suspension]]

@@ Line 35: / Line 35: @@
 ===Inboard vs outboard drive/brake===
-The forces through the suspension members also depend on the brake/drive set up. It is therefore crucial to consider the type of setup in the calculation to properly represent the load paths.
+The forces through the suspension members also depend on the brake/drive setup. It is crucial to consider this in the calculation to properly represent the load paths.
 For an inboard drive/brake, the driveshaft helps and reacts the moment that originates from the contact patch as the driveshaft itself is being stressed. For outboard drive/brake, the driveshaft is not stressed, and cannot transmit the torque like in the inboard scenario. Therefore, with an inboard layout, the driveshaft acts like a 7th link and typically reduces the loads going through the other suspension links. This can be compensated for in the calculation by the additional moment, My, when analysing inboard drive/brakes.
 ===Theory===

@@ Line 25: / Line 25: @@
 Numerous papers on this method exist. A google search for "Formula SAE Suspension Forces Matrix" shows a couple, or check the [[Suspension Forces#See Also|See Also]] Section. The rest of this section provides only a summary with a few pictures. The video provides a detailed explanation in a very easy to understand format.
-A ready-to-fill-in excel file, which accompanies the video is available at [https://github.com/fsaeillumina/suspension-forces https://github.com/fsaeillumina/suspension-forces]
+A ready-to-fill-in excel file, which accompanies the video is available at [https://github.com/fsaeillumina/suspension-forces https://github.com/fsaeillumina/suspension-forces] {{#ev:youtube|https://youtu.be/rhqZQ9Lic2o|600|center|Formula SAE Suspension Forces Matrix Video|frame}}
 ===Assumptions===
 Because all of these have spherical bearings on both ends, they are two-force-members, so they will only see tension/compression forces. If the push/pull rod is mounted to a control arm, then it will introduce bending forces in that control arm. In order to calculate the axial forces in all 6 tubes, it will be assumed that they are all two-force members.
-Acceleration of the wheel assembly is ignored ignored here for simplicity.
+Acceleration of the wheel assembly is ignored here for simplicity.
@@ Line 41: / Line 48: @@
 ===Solving===
 A summary of the solution is given here. It is a decently long process. It is recommended the reader follow through a paper, or watch a video.